Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Theres not a photo there, or like i cant see one x
<span>A is the correct answer. Diploid cells all contain two sets of chromosomes. Prophase 1 occurs during the first phase of meiosis, a type of cell division, and prophase 2 is the same process, but this time occurring without chromosome reduplication. As a result, there is the original and duplicated cells, which makes two.</span>
Answer:
9:enforcement terrorism, 10:true,11:true
