Answer: y=(x+7)^2-9 where h=-7 and k=-9
Step-by-step explanation:
We need to "complete the square",
A perfect square trinomial formule is:
(a+b)^{2}=a+2ab+b^{2}
in this case, a is x and to find -h we know that 14x is 2*x*(-h) so:
14x=2*x*(-h)
14x/2x=-h (x is simplified)
7=-h => h=-7
we add +7^2 and -7^2, to the first equation:
y= <u>x^2 + 14x + 7^2</u> -7^2 + 40 (the underlined section is a perfect square trinomial already)
y=(x+7)^2 <u>-49 +40</u> (addition)
y= (x+7)^2 - 9

We know:
in I and II quadrant
in II and III quadrant
Therefore your answer is:
<h3>θ is in II quadrant</h3>
Answer:
Nothing is hard if you put your mind to it.
Step-by-step explanation:
The first picture is for number 1 and the second one for number 2.
Answer:
Solution of the system of equations: (1, 1)
x = 1, y = 1
Explanation:
Given the below system of equations;

Note that the slope-intercept form of the equation of a line is given as;

where m = slope of the line
b = y-intercept of the line
Comparing the given system of equations with the slope-intercept equation, we can see that, for the 1st equation (y = -3x + 4), the slope(m) = -3 and y-intercept(b) = 4 and for the 2nd equation, slope(m) = 3 and y-intercept(b) = -2.
Knowing the above information, let's go ahead and graph the system of equations;
From the above graph, the point of intersection of the two lines (1, 1) is the solution of the system of equation.