Using the given information, we see that LOM + MON =LON. Now, we just substitute the expressions/numbers and simplify:
(2x+33)+(3x+20)=113
2x+33+3x+20=113
Simplify
5x+53=113
Collect like terms
5x=60
Divide by 5 on both sides to isolate x
x=12
Now we have found the value of x, we can find the value of MON.
MON = 2x+33
MON = 2(12)+33
MON = 24+33
MON = 67°
B=10
<span>sides (a,b,c): 7, 10, 9.4873 </span>
<span>angles (A,B,C): 42°, 72.921°, 65.079° is an acute scalene triangle </span>
<span>(x,y) Vertices: A (4.2137,9.0689) , B (7,0) , C (0,0)
</span><span>Second solution: </span>
<span>sides (a,b,c): 7, 10, 5.3756 </span>
<span>angles (A,B,C): 42°, 107.079°, 30.921° is an obtuse scalene triangle </span>
<span>(x,y) Vertices: A (8.5788,5.1386) , B (7,0) , C (0,0)</span>
First we simplify like terms:
4x-2x+1/2-5/7=1/2-x
2x-3/14=1/2-x
Then you add x to both sides to get everything with the variables together.
3x-3/14=1/2
Finally, you add 3/14 to both sides for the same reason.
3x=10/14 (simplifies to 5/7)
Then we divide by 3 to get x alone.
x=5/21
To have a remainder 3, we take away 3 from each number first.
<u>Take away 3:</u>
224 - 3 = 221
250 - 3 = 247
302 - 3 = 299
<u>Prime factorisation of each of the numbers:</u>
221 = <span>13 x 17
247 = 13 x 19
299 = 13 x 23
<u>Find HCF:</u>
HCF = 13
Answer: The largest number that can be divided is 13.</span>
