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ivolga24 [154]
4 years ago
14

Dallison cooked a 5-pound roast for supper. What is the estimate mass in grams

Mathematics
1 answer:
Lisa [10]4 years ago
4 0

Answer:

Estimated mass of cooked food is 2267.96185 grams

Step-by-step explanation:

The total dinner cooked = 5 pounds

Now by the Parametric Conversion, we know that

1 pound = 453.59237 grams

So, converting the total mass of food in grams, we get

5 pound roast = 5 x 453.59237 grams roast

= 2267.96185 grams

⇒ 5 Pounds = 2267.96185 grams

So, estimated mass of cooked food is 2267.96185 grams.

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A doctor recommends a two-step process to treat a rare form of pancreatic cancer. The first method is successful 80% of the time
Rudiy27

Answer:

The answer is 15%.

Step-by-step explanation:

The probability that:

  • Both treatments are successful:

       80% x 90% = 72%

  • The first method is a success, but the second one is not:

        80% x (1 - 90%) = 8%

  • The first method is not successful, but the second one is:

        (1 - 80%) x 25% = 5%

  • Both treatments are unsuccessful:

        1 - (72% + 8% + 5%) = 15%

5 0
4 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
3 years ago
Simplify 8BC - 9BC + 10BC - 6BC​
never [62]

Answer:

3BC

Step-by-step explanation:

8BC - 9BC + 10BC - 6BC = BC(8 - 9 + 10 - 6) = BC(3) = 3BC

7 0
3 years ago
Read 2 more answers
What is the volume of a Sphere with the radius of 12cm?
kramer

Answer:

I think the answer would be

V≈7238.23cm³

6 0
3 years ago
Read 2 more answers
Please explain to the point a dummy will understand
valkas [14]

Answer:

pretty sure its 18*5

Step-by-step explanation:

1. Solve 3^2 (three squared)

3 x 3= 9

2. Replace 3^2 with 9

it should now look like this:

2*9*5

3. Multiply left to right

2*9= 18

18*5

hope this helps :p

5 0
3 years ago
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