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patriot [66]
3 years ago
12

Oompah’s generally have blue faces, which are caused by a dominant gene. The recessive condition results in an orange face. Deve

lop a “key” using the letter B to show all the possible genotypes and phenotypes for the Oompah face colors. (YOU DO NOT NEED TO DO A PUNNETT SQUARE FOR THIS QUESTION!
BB -
Bb -
Bb -
Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
BB- Blue face 25%
Bb- Blue face 50%
Bb- Blue face( this one is the same exact one as the one above)

if you have a bb it will be orange faced. this is 25%
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Two cones are similar. The surface area of the larger cone is 65π square inches. The surface area of the smaller cone is 41. 6π
kow [346]

Answer: 145

Step-by-step explanation: I say this because it has 14. 4 then

4 0
3 years ago
PLZZ HELP!!!!!!! PLZ ANSWER a.__________ b._________ and c.__________
grandymaker [24]

Answer:

A - 25%

B - 100%

C - 75%

Step-by-step explanation:

I'm pretty sure. Hope this helps. If the shape is divided into 4 equal parts, each one would be worth 25%.

3 0
3 years ago
What is the perimeter of triangle ABC? Round each step to the nearest tenth. Please help me
Ad libitum [116K]

I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².

Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.

Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.

Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.

Add each length up and you get a perimeter of roughly 11.4

8 0
4 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
3 years ago
Please help me with this question!
Reil [10]

\cos(theta)  =  \frac{60}{61}

7 0
3 years ago
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