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Ber [7]
3 years ago
8

Write as an improper fraction and mixed number

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0
Improper: 6 5/10
Mixed number: 63/13
laiz [17]3 years ago
3 0

Answer:

4 8/10 48/10, there ya go

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1/4(x+3)+3/8x=13/4 SOLVE FOR X
larisa86 [58]
1. First I turned the fractions into decimals, just to make things easier for me.2. That gave me => (.25x)+(.75)+(.375)=(3.25)
3. Then, I combined like terms and move my equation around; so, that gave me (.25x) = (3.25) - (.75) - (.375) and when I solve the right side of the equation it gives me
(.25x) = (2.125)
4. After combining like terms and simplifying (the way I did in step 3), I will divide both sides by .25, to get the value of X alone; so, my equation then looks like => x=8.5

4 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Find the difference <br><br><br>-2(c + 2.5) - 5(1.2c + 4)​
Vikentia [17]
Answer:
|−∣=7
Explanation:

∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7
8 0
3 years ago
Linda has a part-time job at the school. She makes between 44.00 and $51.00 a dayWhich is a reasonable estimate of the amount of
Luba_88 [7]

Answer:

$285

Step-by-step explanation:

The mode of 44 and 51 is 47.50 and 47.50 x 6 equals 285

6 0
4 years ago
A 90-kg astronaut biologist searches for microbial life on Mars where the gravitational acceleration is g = 3.71 m/s2. What is t
Yuki888 [10]
M = 90 kg,
On Mars:  g = 3.71 m/s² 
Weight = m · g = 90 kg · 3.71 m/s² = 333.9 N
1 N = 0.2248 lbf
333.9 · 0.2248 = 75.06072 lbf ≈ 75 lbf
5 0
3 years ago
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