All categories

3 years ago

A compound machine is also called a _____ machine.

Physics

1 answer:

SCORPION-xisa [38]3 years ago

7 0

Complex. They both mean a machine which involves two or more simple machines.

You might be interested in

THE LARGEST HORIZONTAL PLATES IS SEPARATED BY 4mm .The plate is at the potencial of -6V . What potencial should be applied to th

Serhud [2]

Answer:

V₂ = -22 V

Explanation:

Electric potential and field are related

ΔV = - E d

where ΔV is the potential difference between the plates, E the electric field and d the separation between the plates

In this exercise we are given the parcionero d = 4 mm = 0.004 m, the potential of one of the plates V1 = -6V and the value of the electric field E = 4000 V / m

V₂- V₁ = - E d

V₂ = - Ed + V₁

V₂ = - 4000 0.004 + (- 6)

V₂ = -16 - 6

V₂ = -22 V

6 0

3 years ago

What is the American psychology Association ethical principle of psychology and code of conduct based upon

solmaris [256]

The correct answer is B

4 0

3 years ago

If a ball leaves the ground with a vertical velocity of 5.46 m/s, how long does it take

kifflom [539]

Answer:

0.557 s

Explanation:

Given:

v₀ = 5.46 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 5.46 m/s

t = 0.557 s

8 0

3 years ago

The SI system uses three base units. Is this true or false?

ozzi

$The\text{ SI }system\text{ uses seven }base\text{ units, hence the statement is false}$

8 0

1 year ago

Read 2 more answers

8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer

Sonbull [250]

Answer:

the distance that the object is raised above its initial position is 5.625 m.

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

$M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \ by \ the \ effort}{disatnce \ moved \ by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m$

Therefore, the distance that the object is raised above its initial position is 5.625 m.

3 0

3 years ago