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pav-90 [236]
4 years ago
9

A compound machine is also called a _____ machine.

Physics
1 answer:
SCORPION-xisa [38]4 years ago
7 0

Complex. They both mean a machine which involves two or more simple machines.

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Can someone explain which of Newton’s Law is demonstrated in part 1 and which is demonstrated in part 2? (Picture)
rewona [7]

Answer:

Every action has an equal and opposite reaction. If the student doesn't push, nothing moves, is one student pushes, both move which is an example of newtons third law.

Explanation:

3 0
3 years ago
Can someone help with this???
Rus_ich [418]

no BECQUSE POSUM BROOB SHSHSJ

8 0
3 years ago
Read 2 more answers
El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propa
TiliK225 [7]

Answer:

v = 2,99913 10⁸ m / s

Explanation:

The velocity of propagation of a wave is

         v = λ f

in the case of an electromagnetic wave in a vacuum the speed that speed of light

         v = c

When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium

         λ = λ₀ / n

where n is the index of refraction of the material medium.

Therefore the expression is

           v = \frac{\lambda_o}{n} f

Let's look for the frequency of blue light in a vacuum

           f =\frac{c }{\lambda_o}  

           f = \frac{3 \ 10^8}{450 \ 10^{-9}}

           f = 6.667 10¹⁴ Hz

the refractive index of air is tabulated

           n = 1,00029

let's calculate

           v = \frac{450 \ 10^{-9} }{1.00029}  \ 6.667 \ 10^{14}450 10-9 / 1,00029 6,667 1014

            v = 2,99913 10⁸ m / s

we can see that the decrease in speed is very small

8 0
3 years ago
What’s being done to the brake fluid in the above photo?
ch4aika [34]

Answer:

D. Checking to see if the brake fluid is contaminated

Explanation:

5 0
3 years ago
On a horizontal frictionless surface, a small block with mass 0.200 kg has a collision with a block of mass 0.400 kg. Immediatel
Akimi4 [234]

Answer:48.2 Joules

Explanation:

Given

two masses of 0.2 kg and 0.4 kg collide with each other

after collision 0.2 kg deflect 30 north of east and 0.4 kg deflects 53.1 south of east

Velocity of 0.2 kg mass is

v_{0.2}=12\cos (30)\hat{i}+12\sin (30)\hat{j}

|v_{0.2}|=11.99 m/s\approx 12 m/s

Velocity of 0.4 kg mass

v_{0.4}=13\cos (53.1)\hat{i}-12\sin (53.1)\hat{j}

|v_{0.4}|=12.99 m/s\approx 13 m/s

Thus total Kinetic energy =\frac{0.2\times 12^2}{2}+\frac{0.4\times 13^2}{2}

Kinetic energy=48.2 J

8 0
3 years ago
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