3 years ago

PLS HELP BEST PRESENT EVER!!!!!!!!!!!!!

Physics

1 answer:

galina1969 [7]3 years ago

6 0

velocity=distance/time

v=d/t

v=4.77m/19.5s=0.24m/s

You might be interested in

Which property increases as an electromgnetic waze's decreases

kirza4 [7]

Answer:

the frequency decreases

Explanation:

As a wave's wavelength increases, the frequency decreases

4 0

3 years ago

A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball i

sveticcg [70]

Answer:

a) 72.54° and It will take the woman 33.4m

Explanation:

The woman runs with a constant speed V1 = 6m/s

V2 = 20m/s

V1 = V2 cos θ

Cos θ= V1/V2= 6/20

Cos θ= 0.3

Cos^-1 0.3=72.54°

Using Range formular for projectile

R= (V2 Cos θ)/g (V2 Sin θ)^2 +sqrt(V2 Sin θ)^2 + 2gh)

R= (20cos72.54)(2Sin72.54+sqrt(20Sin72.54)^2 + 2×9.8×45

R=33.4m

b )

see the attached file

7 0

3 years ago

a technician connects the red lead of a voltmeter to the b+ [output] terminal of an ac generator and the black lead to the batte

stealth61 [152]

Answer:

He is testing for voltage drop (voltage drop test)

Explanation:

Connecting the red lead of a voltmeter to the B+ output to an ac generator and black lead to a battery +ve terminal measures the voltage drop in the circuit when the engine is turned ON and all electrical accessories too.

with this he knows if the alternator is charging the battery.

8 0

4 years ago

Un auto se mueve con velocidad constante de 20 m/s y la mantiene durante 20 s. Después se le aplica una aceleración constante y

pentagon [3]

Answer:

26.67 s

Explanation:

v = Velocidad final = 40 m/s

u = Velocidad inicial = 20 m/s

$t_1$ = Tiempo inicial = 20 s

$t_2$ = Tiempo empleado durante la aceleración

a = Aceleración

s = Desplazamiento del automóvil durante la aceleración = 200 m

De las ecuaciones lineales de movimiento tenemos

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{40^2-20^2}{2\times 200}\\\Rightarrow a=3\ \text{m/s}^2$

$v=u+at_2\\\Rightarrow t_2=\dfrac{v-u}{a}\\\Rightarrow t_2=\dfrac{40-20}{3}\\\Rightarrow t_2=6.67\ \text{s}$

El tiempo necesario para acelerar es 6.67 s

El tiempo total necesario para toda la ruta es $t=t_1+t_2=20+6.67=26.67\ \text{s}$ .

4 0

3 years ago

1 jWhat is the correct unit for temperature? <br>

Nadya [2.5K]

Answer:

Answer: Kelvin ________________

8 0

3 years ago