Explanation:
(a) Net force acting on the block is as follows.
or, ma = -mg Sin (\theta)[/tex]
a =
=
= -3.35
According to the kinematic equation of motion,
Distance traveled by the block before stopping is as follows.
s =
=
= 21.5 m
According to the kinematic equation of motion,
v =
0 =
= 7.16 sec
Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.
(b) When the block is moving down the inline then net force acting on the block is as follows.
ma =
a =
=
= 3.35
Kinematics equation of the motion is as follows.
s =
21.5 m =
=
= 3.58 sec
Hence, total time taken by the block to return to its starting position is as follows.
t =
= 7.16 sec + 3.58 sec
= 10.7 sec
Thus, we can conclude that 10.7 sec time it take to return to its starting position.
Answer:
16 years.
Explanation:
Using Kepler's third Law.
P2=D^3
P=√d^3
Where P is the orbital period and d is the distance from the sun.
From the question the semi major axis of the asteroid is 4 AU= distance. The distance is always express in astronomical units.
P=?
P= √4^3
P= √256
P= 16 years.
Orbital period is 16 years.
Umm the rocks warm up until it becomes a not rock anymore and becomes really hot then it get so hot it starts coming out of a mountain called a volcanoe
Yes. 'Equilibrium' means that the SUM of adding up all the forces acting on the object is ZERO.
If you add up all the forces acting on the object and the sum is NOT zero, then the object is NOT in equilibrium. The force you have to add to it is whatever it takes to cancel out (balance) all the forces that are there now.
Take the SUM you got when you added up all the existing forces. To get equilibrium, ADD ON one new force with the SAME magnitude, in exactly the OPPOSITE direction.
Hey I thought we were going out tonight but we are going out to dinner with the girls and we will go back together lol I have a nice weekend and we will go aback lol I love it so I can go get my food and I can eat tonight and go back home.