Explanation:
1 mol of ZrSiO₄ , have , 1 mol of Zr , 1 mol of Si and 4 mol of Oxygen .
since ,
1 mol of a substance have 6.022 * 10 ²³ particles ,
From the question ,
0.3384 mol of zircon ZrSiO₄ ,
hence ,
from the above equation ,
1 mol of a substance have 6.022 * 10 ²³ particles ,
0.3384 mol = 0.3384 * 6.022 * 10 ²³ number of atoms
= 2.037 * 10 ²³ number of atoms
Hence ,
0.3384 mol of ZrSiO₄ will have , 0.3384 mol of Zr ,0.3384 mol of Si and 4*0.3384 mol of Oxygen .
Hence ,
- number of atoms of Zr = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms
- number of atoms of Si = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms
- number of atoms of O = 4 * 0.3384 mol * 6.022 * 10 ²³ = 8.148 * 10 ²³ number of atoms
The mass is calculated as -
since ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
n = w / m
w = n * m
Since we know , the molecular mass of Zr = 91 g/mol
moles of Zr = 0.3384 mol
using the above formula ,
w = n * m
w = 0.3384 mol * 91 g/mol = 30.79 g
hence ,
The mass of Zr = 30.79 g
Since we know , the molecular mass of Si = 28 g/mol
moles of Si = 0.3384 mol
using the above formula ,
w = n * m
w = 0.3384 mol * 28 g/mol = 9.475 g
hence ,
The mass of Si = 9.475 g
Since we know , the molecular mass of O = 16 g/mol
moles of Si = 1.3536 mol
using the above formula ,
w = n * m
w = 1.3536 mol * 16 g/mol = 21.65 g
hence ,
The mass of O = 21.65 g
