1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vova2212 [387]
3 years ago
15

What is the mass of the question?

Chemistry
1 answer:
musickatia [10]3 years ago
6 0

Answer: I do not know

Explanation:

You might be interested in
Andi performs the calculation that is shown below.
rodikova [14]

Answer: 3.59

Explanation:

(2.06)(1.743)(1.00)

2.06 × 1.743 × 1.00

= 3.59058

Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.

3.59058 to 3 significant figures:

First three digits = 3.59

Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits

Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :

3.59

3 0
3 years ago
Which atom would be expected to have a half-filled <br> 3d subshell?
lana66690 [7]

Answer:

Manganese: Mn

Explanation:

The elestron configuration would show this is 25 electrons

Atomic number : 25

this electron configuration ends in 3d^{5}

half of the d subshell which is 10

6 0
3 years ago
You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
What volume is equivalent to 12.0 m^3?
anzhelika [568]

1.2 x 10^10 mm^3 is equivalent to 12.0 m^3

8 0
3 years ago
The jet stream is one of the key winds that moves air masses. in which direction does the jet stream in the united state general
OleMash [197]

The jet stream is one of the key winds that moves air masses at the direction from west to east it moves.

<h3>What are jet streams?</h3>

Jet streams are strong winds which are flow in the form of narrow bands in the upper part of the atmosphere. On the earth these winds are flows near the altitude of the tropopause. These winds carries weather systems and blows toward the colder northern air and due to the rotation of earth, its direction is from west to east.

Hence jet streams move winds from west to east direction.

To know more about jet streams, visit the below link:
brainly.com/question/791542

7 0
2 years ago
Other questions:
  • What is the cell potential of an electrochemical cell that has the half -reactions shown below? Ni^ 2+ +2e Ni A| A|^ 3+ +3e^ -
    8·1 answer
  • Find the volume occupied by 18.0 g of helium gas at 29.0 ∘c and 1.33 atm of pressure.
    15·1 answer
  • Convert 732.0 mmHg to atm
    7·1 answer
  • Describe the behavior of electrons in single, double, and triple bonds. Compare and contrast their properties, listing an exampl
    15·1 answer
  • What type(s) of atoms make up the element carbon?
    13·2 answers
  • A researcher is using a small molecule as an inhibitor to manipulate a signaling pathway. This inhibitor prevents phosphorylatio
    9·1 answer
  • Can someone figure this out for me thank you
    5·1 answer
  • Which species is the conjugate base of H2SO3
    14·1 answer
  • Oi oi oi oi ewin <br> .................
    10·1 answer
  • Within atoms, what kind of energy<br> is stored?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!