Answer:
for (scores.Entry<String, Integer> entry : scores.entrySet()) {
int value=0; String key="Rambo";
String k = entry.getKey();
int v = entry.getValue();
if (v>value)
{
value =v;
}
else
{
value=value;
}
}
for( scores.Entry<String, Integer> entry : scores.entrySet())
{
if( entry.getValue()==value)
System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
}
Explanation:
The above scores are an object of Map type. And this is a parameter of findUopStudent function. So scores is a Map, and entry is an item. And we get its key and value. Now we compare each value using senteniel method and find the maximum value. Now we iterate through the scores using for the look and check the value of each entry against the maximum value found, and we print out the entry with maximum value. And that is the top student, which is required.
Answer:
Multitasking is a process in which we do multiple task at a time.
In computing system, multitasking is the concept of performing different types of multiple task and process over a certain period of time by executing simultaneously.
Operating system basically allow various task to run simultaneously by the user. In an operating system, each task consume storage system and all the other resources.
Multitasking function facilitate memory isolation in the processor and also supported different levels of security system in the operating system. For example, "a programmer working on any program in a system and as well as listening the music then, it perform multiple task at the same time".
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
