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3 years ago

5

Triangle CDE has been rotated 90° in a clockwise direction. Based on the figure, which would be a correct name for the image of

the figure after the rotation?

2 answers:

Goryan [66]3 years ago

7 0

Answer:

C'D'E'

Step-by-step explanation:

Alex17521 [72]3 years ago

5 0

Answer:C’D’E’

Step-by-step explanation:I just did it

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PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Bond [772]

Answer:

$R = \frac {3ST}{2S + T}$

Step-by-step explanation:

Given the equation;

$\frac {3}{R} - \frac {1}{S} = \frac {2}{T}$

Rearranging the equation, we have;

$\frac {3}{R} = \frac {2}{T} + \frac {1}{S}$

Lowest common multiple (LCM) of S and T is ST.

$\frac {3}{R} = \frac {2S + T}{ST}$

Cross-multiplying, we have;

$3ST = R(2S + T)$

Making R, the subject of formula;

$R = \frac {3ST}{2S + T}$

8 0

3 years ago

7×6 = 42 that means that six and seven are factors of 42 true or false explain

schepotkina [342]

Answer:

Step-by-step explanation:true by multiplying 6x7=42

5 0

2 years ago

A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th

Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0

2 years ago

According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110

sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0

2 years ago

WILL GIVE BRAINLIEST!!

NNADVOKAT [17]

The second one should be correct

8 0

2 years ago