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Nina [5.8K]
3 years ago
8

what is the perimeter of triangle PQR vertices P(-2, 9), Q(7,-3), and R(-2, -3) in the coordinate plane?

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0
This is a diffficult question was there a chart
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Consider the intersecting lines shown. Which of the following statements could you prove based on this?
shepuryov [24]

Answer:

Step-by-step explanation:

Answer D I just fot it right on my test

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3 years ago
What is it called when transformation of the plane which reflects each point and then translates it called
Crank

The figures in a plane can be reflected, rotated, translated or dilated to produce new figures or images.

A transformation that moves all points to the same distance and in the same direction. The final figure looks the same, just moved over. It does not flip or gets rotated. It also does not change size.This type of translation is called glide reflection. Its the summation of translation and reflection.

6 0
3 years ago
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2. G.GPE.7 Consider ∆ABC below. What is the perimeter of ∆ABC? * A. 16.9 B. 12.9 C. 18.6 D. 17.4
dsp73

Answer:B

Step-by-step explanation:

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2 years ago
Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
3 years ago
The area of a parallelogram is 88.58 sq cm. The length of the base is 8.6 cm. What is the height?​
Evgen [1.6K]

Answer:

10.3 is the length

Step-by-step explanation:

If the area of a parallelogram is B * H then finding one side is dividing area by base or by height

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