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Lilit [14]
3 years ago
7

75y^3+100y^2-3y-4=0

Mathematics
1 answer:
sweet [91]3 years ago
7 0
Move all terms to the left side and set equal to zero. Then set each factor equal zero.
y = -4/3, 1/5, 1/5
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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
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Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

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Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

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16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

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Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

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