Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
Sigma is the eighteenth letter of the Greek alphabet. In the system of Greek numerals, it has a value of 200. In general mathematics, uppercase ∑ is used as an operator for summation. When used at the end of a letter-case word, the final form is used
Step-by-step explanation:
Answer:
-8 -6 -3 4
Step-by-step explanation:
In a number line, the numbers on the are lesser than the numbers on the right. In a number line with integers, numbers going to the right from the midline which is 0 is positive and increases as you move to the right. As you move to the left, the numbers are negative and decreases as you move further to the left.
Attached is a picture of how it would look on a number line.
Don’t let the letter scare you, imagine this as a simple cross product!
(32 × 1) ÷ 8 = m
32 ÷ 8 = m
4 = m
There you go, the solution to this equation is that m = 4!
I really hope this helped, if there’s anything just let me know! ☻
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right
