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3 years ago

Can anybody correct me on this right away if you got any time? click/tap in here for the image

Mathematics

1 answer:

Mandarinka [93]3 years ago

8 0

Answer:

Yep, they all match:

1. Correct

2. Correct

3. Correct

4. Correct

Step-by-step explanation:

√2 • √3 • √3 = 4.242640687119285‬

3√2 = 4.242640687119285‬

√2 • √3 • √-3 = 4.24264069i

3i√2 = 4.24264069i

√-2 • √-3 • √-3 = -4.24264069i

-3√2 = -4.24264069i

√2 • √-3 • √-3 = -4.24264069i

-3i√2 = -4.24264069i

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Lin bought x grams of sugar. Jada bought 3⁄4 more than that. what is the equation that will represents the relationship between

astra-53 [7]

Answer:

y = 7/4x

Step-by-step explanation:

Lin bought x grams of sugar.

Jada bought 3⁄4 more than Lin bought.

The equation:

y = x + 3/4x ⇒ y = 7/4x

3 0

2 years ago

A and B are independent events. P(A) = 0.50 P(B) = 0.30 What is P(A/B)? a. not enough information. b. 0.30 c. 0.50 d. 0.15

Gala2k [10]

Answer:

0.50

Step-by-step explanation:

P(A|B)=P(A and B)/P(B) is the formula to find a conditional probability when A and B are not independent.

A and B are independent. This means B has no effect of A. This means P(A|B)=P(A).

P(A|B)=P(A) since A and B are independent

P(A|B)=0.50

3 0

3 years ago

8.41 x 7.82 x 414 40.6 x 80.22 What is the awnser

Zina [86]

Answer:

the answer that i got was 88677161.1

Step-by-step explanation:

i just multiplied all of them together, hope it helps

6 0

3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

3 years ago

Teds science class collects aluminum cans to sell to the recycling center. the center pays a fixed amount for each kilogram of a

tatuchka [14]

The Center Pays $0.002 For Each Kilogram

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3 years ago

Can anybody correct me on this right away if you got any time? click/tap in here for the image​

Can anybody correct me on this right away if you got any time? click/tap in here for the image