Answer:
921b-199
Step-by-step explanation:
Answer:
If Discriminant,
Then it has Two Real Solutions.
Step-by-step explanation:
To Find:
If discriminant (b^2 -4ac>0) how many real solutions
Solution:
Consider a Quadratic Equation in General Form as
then,
is called as Discriminant.
So,
If Discriminant,
Then it has Two Real Solutions.
If Discriminant,
Then it has Two Imaginary Solutions.
If Discriminant,
Then it has Two Equal and Real Solutions.
Answer:
0. | 2
Step-by-step explanation:
I took (0.2) and made an equal sign and gave me 0. | 2
Answer:
0,05
Step-by-step explanation:
1)First, Let’s find the mean of the data table
12 + 10 + 12 + 6 + 8 + 4 + 2 + 12 = 66
66 ÷ 8 = 8,25
2)12 - 8,25 = 3,75
10 - 8,25 = 1,25
12 - 8,25 = 3,75
6 - 8,25 = -1,75
8 - 8,25 = -0,75
4 - 8,25 = -3,75
2 - 8,25 = -5,75
12 - 8,25 = 3,75
3) 3,75 + 1,25 + 3,75 - 1,75 - 0,85 - 3,75 - 5,75 + 3,75 = 0,4
0,4 ÷ 8 = 0,05
Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
