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coldgirl [10]
4 years ago
12

Give a big-o estimate for the number of operations (where an operation is an addition or a multiplication) used in this segment

of an algorithm. t := 0 for i := 1to3 for j := 1to4 t := t + ij
Mathematics
1 answer:
Marianna [84]4 years ago
6 0
We have a "rectangular" double loop, meaning that both loops go to completion.
So there are 3*4=12 executions of t:=t+ij.

Assuming two operatiions per execution of the innermost loop, (i.e. ignoring the implied additions in increment of subscripts), we have 12*2=24 operations in all.

Here the number of operations (+ or *) is exactly known (=24). 

Big-O estimates are used for cases with a varying scale of operations, governed by a variable (usually n) to indicate the sensitivity of the number of operations relative to a change in the size of n.

Here we do not have a scale, nor n is defined.  The number of operations is constant and known at 24.   So a variable is required to find the big-O estimate.
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Answer:

not a solution

Step-by-step explanation:

y < 7x + 8

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-6 < 7(-2) +8

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The congruence theorem that can be used to prove ALON
Arisa [49]

Answer:

SSS is the congruence theorem that can be used to prove Δ LON  is congruent to Δ LMN ⇒ 1st answer

Step-by-step explanation:

Let us revise the cases of congruence

  • SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
  • SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
  • ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
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In triangles LON and LMN

∵ LO ≅ LM ⇒ given

∵ NO ≅ NM ⇒ given

∵ LN is a common side in the two triangles

- That means the 3 sides of Δ LON are congruent to the 3 sides

   of Δ LMN

∴ Δ LON ≅ LMN ⇒ by using SSS theorem of congruence

SSS is the congruence theorem that can be used to prove Δ LON  is congruent to Δ LMN

3 0
4 years ago
What is 30,000 expressed in scientific notation?
4vir4ik [10]

Answer:

B

Step-by-step explanation:

Hope this helps : )

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Use the same coordinate plane to draw the graphs of the functions. Y=kx-2 if k=1, 0.4,-1
mario62 [17]

Graphs can be used to represent functions.

See attachment for the graphs of: <em>y =x - 2, y = 0.4x - 2, y =-x - 2</em>

The function is given as: \mathbf{y = kx - 2}

When k = 1,

We have:

\mathbf{y = 1\times x - 2} ----- substitution property of equations

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So, the equation is: \mathbf{y = x - 2} when k = 1

When k = 0.4,

We have:

\mathbf{y = 0.4\times x - 2} ----- substitution property of equations

\mathbf{y = 0.4x - 2}

So, the equation is: \mathbf{y = 0.4x - 2} when k = 0.4

When k = -1,

We have:

\mathbf{y = -1\times x - 2} ----- substitution property of equations

\mathbf{y = -x - 2}

So, the equation is: \mathbf{y = -x - 2} when k = -1

See attachment for the graphs of: \mathbf{y = x - 2}, \mathbf{y = 0.4x - 2} and \mathbf{y = -x - 2}

Read more about graphs and functions at:

brainly.com/question/11804653

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