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MariettaO [177]
3 years ago
8

Which points are on the graph of the inverse?

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0
The points (1,-1) and (0, 0) lie on the line y=x and will be included on both graphs. 

When a graph is inversed, the coordinates are also flipped. (-9, 3) also switches the sign, which is not a part of the inverted graph. 

The other option (4, 2) is a flip on the given coordinates (2, 4) and would be present on the inverted graph. 
Klio2033 [76]3 years ago
3 0
The difference of a function and its inverse is found by switching x and y
so if the function is (2,3)...then its inverse is (3,2)

(4,2)....correct
(1,-1)...correct
(0,0)...correct

I agree with ur answers



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2 years ago
I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


3 0
3 years ago
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