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Natalija [7]
2 years ago
8

(b) Factorise fully 2 a²b + 6ab2

Mathematics
2 answers:
den301095 [7]2 years ago
6 0

Answer:

<h2>2ab(a+3b)</h2>

Step-by-step explanation:

2 {a}^{2} b + 6a {b}^{2}

Factor out common term : 2ab

2 {a}^{2}b \div 2a = a \\ 6a {b}^{2}  \div 2ab = 3b  \\ 2ab(a + 3b)

Juliette [100K]2 years ago
4 0

2a^2b+6ab^2

Perhaps, you mean 6ab² (If not please remind me.)

Factoring the polynomials can be done by pulling out the terms that can be divided by that terms.

For example, 2x^2+4    We can divide the whole polynomial by 2. Thus, we factor 2 out of the polynomial as we get 2(x^2+2) -- Factoring is like dividing, but instead - we pull them out.

Now let's get back to the question.

Notice that the polynomial can be divided by 2, a and b.

So we pull 2, a and b out of the polynomial and divide them.

\frac{2a^2b+6ab^2}{2ab}\\a+3b

When dividing, we should get a + 3b.

Then we pull out 2ab outside the bracket.

2ab(a+3b)

Thus, the answer is 2ab(a+3b)

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–2x + 2y = -4<br> 3х + Зу = -18
rodikova [14]

Answer:

(-2, -4)

Step-by-step explanation:

–2x + 2y = -4

3х + Зу = -18

Divide the first equation by 2

–2x/2 + 2y/2 = -4/2

-x +y = -2

Divide the second equation by 3

3х/3 + Зу/3 = -18/3

x + y = -6

Add these equation together

-x +y = -2

x + y = -6

-------------------

0x + 2y = -8

2y = -8

Divide each side by 2

2y/2 = -8/2

y = -4

Now we need x

x+y = -6

x-4 = -6

Add 4 to each side

x-4+4 = -6+4

x = -2

3 0
3 years ago
Plz explain.
slega [8]
Idk, why does the world need problems like this, not like everyone is going to grow up to be a math teacher.
8 0
2 years ago
Solve the following systems of inequalities and select the correct graph: 2x-y&gt;4 x+y&lt; -1
Serga [27]

Answer:

Step-by-step explanation:

2x - y > 4 ⇒ y < 2x - 4

x + y < - 1 ⇒ y < - x - 1

3 0
2 years ago
Read 2 more answers
The Happy Hacker electronics warehouse purchases 460 USB flash drives, which are then packed in sets of four selling for $24.95
Fittoniya [83]

Answer:

2869.25

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Is (-1,2) a solution of the system y&gt;x and x+y=&gt;
valentina_108 [34]
(-1,2) is a solution

y>x

2>-1 is correct

in this case yes

x+y≥x

 -1+2≥-1 

1≥-1 is correct: Yes

in this case no

x+y≥y

1≥2 

is not correct. No


8 0
3 years ago
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