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Natalija [7]
2 years ago
8

(b) Factorise fully 2 a²b + 6ab2

Mathematics
2 answers:
den301095 [7]2 years ago
6 0

Answer:

<h2>2ab(a+3b)</h2>

Step-by-step explanation:

2 {a}^{2} b + 6a {b}^{2}

Factor out common term : 2ab

2 {a}^{2}b \div 2a = a \\ 6a {b}^{2}  \div 2ab = 3b  \\ 2ab(a + 3b)

Juliette [100K]2 years ago
4 0

2a^2b+6ab^2

Perhaps, you mean 6ab² (If not please remind me.)

Factoring the polynomials can be done by pulling out the terms that can be divided by that terms.

For example, 2x^2+4    We can divide the whole polynomial by 2. Thus, we factor 2 out of the polynomial as we get 2(x^2+2) -- Factoring is like dividing, but instead - we pull them out.

Now let's get back to the question.

Notice that the polynomial can be divided by 2, a and b.

So we pull 2, a and b out of the polynomial and divide them.

\frac{2a^2b+6ab^2}{2ab}\\a+3b

When dividing, we should get a + 3b.

Then we pull out 2ab outside the bracket.

2ab(a+3b)

Thus, the answer is 2ab(a+3b)

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add - 7 both sides
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2x  - 6y = 4
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5x + 15y = - 10
add - 15 to both sides
5x + 15y +   - 15y = - 10 +  - 15y
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2x + 6y = 10
add - 6y to both sides
2x + 6y +  - 6y = 10 +  - 6y
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divide both sides by 2
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Hope that helps!!!
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