Answer:
y = 3 - x + x²
Step-by-step explanation:
Given the data:
x. y
-5 33
-2 9
-1 5
0 3
3 9
4 15
6 33
General formof a quadratic model:
y = A + Bx + Cx²
Using the quadratic regression model solver for the data Given:
The quadratic model fit obtained is :
y = 3 - x + x²
It’s a!!!!!!!!!!!!!!!!!!!!!!!!
Joaquin should expect about 51 winners out of 300 players!
I hope this helped! also I love your pfp!!!!!!!
L’ (4.5,0) J’(-4.5, -4.5) K’(-4.5,4.5) i think
Answer:
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 12, \sigma = 3](https://tex.z-dn.net/?f=%5Cmu%20%3D%2012%2C%20%5Csigma%20%3D%203)
What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?
This is 1 subtracted by the pvalue of Z when X = 16. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{16 - 12}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B16%20-%2012%7D%7B3%7D)
![Z = 1.33](https://tex.z-dn.net/?f=Z%20%3D%201.33)
has a pvalue of 0.9082
1 - 0.9082 = 0.0918
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated