Question

∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and minor arc AC = 166, what is the measure of ∠ BEC? A) 44° B) 47° C) 50° D) 53°

Answer 1

Answer:

∠BEC = 50°

Step-by-step explanation:

For better understanding of the solution, see the attached figure of the problem :

Minor arc BD = 94

Minor arc AC = 166

Now, the angle formed by the intersection of the two chords is ∠BED

And, the angle formed by the intersection of two chords is half the sum of angle measures of the corresponding chords.

$\implies \angle BED =\frac{1}{2}\times (BD + AC)\\\\ \implies \angle BED = \frac{1}{2}\times (94+166)\\\\\implies \angle BED=\frac{1}{2}\times 260\\\\\implies\angle BED = 130$

Now, ∠BED + ∠BEC = 180 ( Adjacent angles )

⇒ ∠BEC = 180 - 130

⇒ ∠BEC = 50°

Answer 2

Answer:

The answer is 50

Step-by-step explanation:

bc its just right idk how but it is