Answer:
The answer is explained below
Step-by-step explanation:
The question is not complete we need point P and point Q.
let us assume P is at (3,1) and Q is at (-2,4)
To find the coordinate of the point that divides a line segment PQ with point P at
and point Q at
in the proportion a:b, we use the formula:

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

Answer:
x is the reciprocal of the difference of a and b.
Step-by-step explanation:
ax=bx+1
Subtract by bx on both sides
ax-bx=1
x(a-b)=1
x= 1/(a-b)
SinA=5root3/10
CosA=5/10
TanA=5root3/5=root3
SinC=5/10=1/2=0.5
CosC=5root3/10
Tanc=5/5root3=1/root3
You are comparing velocities. Without a given acceleration, the time can not be found.
To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides

1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself

