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bearhunter [10]
3 years ago
7

15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

. What is the density of this unknown liquid?
A :0.85 g/mL
B :01.18 g/mL
C :0.847 g/mL
D :1.1811 g/mL​
Chemistry
1 answer:
sveticcg [70]3 years ago
4 0

Answer:

\boxed {\tt A. \ d=0.85 \ g/mL}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

m= 12.7 \ g\\v= 15 \ mL

Substitute the values into the formula.

d=\frac{12.7 \ g}{ 15 mL}

Divide.

d=0.846666667 \ g/mL

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

d \approx 0.85 \ g/mL

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

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Answer:

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4 0
3 years ago
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prohojiy [21]

Hey there!:

From the given data ;

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Vmax = 0.758 umole/min/ per mL

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4 0
3 years ago
5,6-dimethyl-2-heptyne <br><br> Due in 1 hr pls help me
mina [271]

Answer:

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4 0
3 years ago
Mr. Swerdlow wrote a chemical equation on the board and asked his class what should be changed to make it correct. He wrote:
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6 0
3 years ago
Read 2 more answers
Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm8 at 27 ∘C. (R =
maxonik [38]

Answer:

Total pressure =  56.77 bar

Explanation:

Given data:

Mass of dioxygen = 8 g

Mass of dihydrogen = 4 g

Volume of vessel = 1 dm³

Temperature = 27°C (27+273 = 300 K)

R = 0.083 bar.dm³ / mol.K

Total pressure = ?

Solution:

Number of moles of dioxygen:

Number of moles = mass/molar mass

Number of moles = 8 g/ 32 g/mol

Number of moles = 0.25 mol

Pressure of dioxygen:

PV = nRT

P = nRT/V

P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 6.97 bar.dm³  /1 dm³

P = 6.97 bar

Number of moles of dihydrogen:

Number of moles = mass/molar mass

Number of moles = 4 g/ 2 g/mol

Number of moles = 2 mol

Pressure of dihydrogen:

PV = nRT

P = nRT/V

P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 49.8 bar.dm³  /1 dm³

P = 49.8 bar

Total pressure of mixture in a vessel:

Total pressure = P (O₂) + P(H₂)

Total pressure =  6.97 bar + 49.8 bar

Total pressure =  56.77 bar

7 0
3 years ago
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