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Whitepunk [10]
3 years ago
10

Based on the information above, do you think that fluorine has common isotopes? Justify your answer.

Chemistry
2 answers:
Simora [160]3 years ago
5 0

Answer is: fluorine does not have common isotopes, because its average atomic mass is 19.

Fluorine has only one isotope occurs naturally in abundance, the stable isotope F-19.

This isotope has:

1) n(p⁺) = 9; fluorine has atomic number Z = 9 (total number of protons).

2) n(e⁻) = 9; in an element, number of electrons and protons are the same.

3) n(n°) = 10; mass number of this isotope is A = 19. Mass nummber is total number of protons and neutrons in a nucleus, so number of neutrons is:  

n(n°) = A-Z.

n(n°) = 19-9.

n(n°) =10.

andre [41]3 years ago
4 0

Answer:

No, it hasn't. Because it has 9 protons and 10 neutrons and its average mass is 19, it has no common isotopes.

Explanation:

An isotope is an atom of the element which has the same atomic number (number of protons), but a different mass number. For example, hydrogen has 3 isotopes: H¹, H², and H³, all with an atomic number equal to 1.

The mass that is represented in the periodic table is the weighted average of the masses of the isotopes, based on the percentage that they're found in nature.

The mass of an atom is concentrated in the nucleus, so it is the mass of the protons plus the mass of the neutrons, which are equal to 1 amu (atomic mass unity).

For the fluorine atom with mass 19.00 and atomic number 9, we can infer it has 10 neutrons. Because the average mass is exactly 19.00 we can infer that all the fluorine atoms have 9 protons and 10 neutrons ( it's easy to observe in the periodic table that the masses are not exactly).

Then, we can infer for the information that fluorine has no common isotopes.

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An alcohol is 68.84 % C and 4.962 % H by mass. The rest is oxygen. What is the empirical formula of the alcohol? Enter the eleme
Dafna1 [17]

The empirical formula is C₇H₆O₂.

Assume that you have 100 g of the compound.

Then you have 68.84 g C and 4.962 g H.

Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.

Now, we must convert these masses to moles and find their ratios.

From here on, I like to summarize the calculations in a table.

<u>Element</u>     <u>Mass/g</u>    <u>Moles</u>    <u>Ratio</u>    <u> ×2</u>   <u>Integers</u>  

     C           68.84      5.732    3.501  7.001       7

     H            4.962    4.923    3.006  6.012      6

     O          26.20      1.638     1          2             2

The empirical formula is C₇H₆O₂.

8 0
3 years ago
BRAINLIEST AND 30 POINTS! concept map for four types of intermolecular forces and a certain type of bond is shown.
Sphinxa [80]

D represents ion-dipole forces that are stronger than the force C.

Explanation:

D represents the ion-dipole force.

C represents the H-bonding forces.

ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.

It is electrostatic in nature.

A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N

Ion dipole force is stronger than the H-bonding.

3 0
3 years ago
PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!
Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

95

mL of water.

8 0
2 years ago
150 ml of 0.1 m naoh is added to 200 ml of 0.1 m formic acid, and water is added to give a final volume of 1 l. what is the ph o
N76 [4]

Number of moles of NaOH = V(NaOH) * M(NaOH)= 0.150 L * 0.1 moles/L = 0.015 moles

Number of moles of formic acid, HCOOH = V(HCOOH) * M(HCOOH) = 0.200 L * 0.1 moles/L = 0.020 moles

Here, the limiting reagent is NaOH

The reaction is represented as:

HCOOH + NaOH ↔HCOONa + H2O

Moles of HCOONa formed = Moles of the limiting reagent, NaOH = 0.015 moles

Moles of HCOOH remaining = 0.020-0.015 = 0.005 moles

Total final volume is given as 1 L

Therefore: [HCOOH] = 0.005 moles/1 L = 0.005 M

[HCOONa] = 0.015/1 = 0.015 M

pKa of HCOOH = 3.74

As per Henderson-Hasselbalch equation

pH = pka + log[HCOONa]/[HCOOH] = 3.74+log[0.015/0.005] = 4.22

Therefore, pH of the final solution = 4.22


                       


3 0
3 years ago
How are you! :D I hope your doing good
Tanya [424]

Answer:

Yeah, Fine..

Explanation:

5 0
2 years ago
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