All categories

2 years ago

Based on the information above, do you think that fluorine has common isotopes? Justify your answer.

Chemistry

2 answers:

Simora [160]2 years ago

5 0

Answer is: fluorine does not have common isotopes, because its average atomic mass is 19.

Fluorine has only one isotope occurs naturally in abundance, the stable isotope F-19.

This isotope has:

1) n(p⁺) = 9; fluorine has atomic number Z = 9 (total number of protons).

2) n(e⁻) = 9; in an element, number of electrons and protons are the same.

3) n(n°) = 10; mass number of this isotope is A = 19. Mass nummber is total number of protons and neutrons in a nucleus, so number of neutrons is:

n(n°) = A-Z.

n(n°) = 19-9.

n(n°) =10.

andre [41]2 years ago

4 0

Answer:

No, it hasn't. Because it has 9 protons and 10 neutrons and its average mass is 19, it has no common isotopes.

Explanation:

An isotope is an atom of the element which has the same atomic number (number of protons), but a different mass number. For example, hydrogen has 3 isotopes: H¹, H², and H³, all with an atomic number equal to 1.

The mass that is represented in the periodic table is the weighted average of the masses of the isotopes, based on the percentage that they're found in nature.

The mass of an atom is concentrated in the nucleus, so it is the mass of the protons plus the mass of the neutrons, which are equal to 1 amu (atomic mass unity).

For the fluorine atom with mass 19.00 and atomic number 9, we can infer it has 10 neutrons. Because the average mass is exactly 19.00 we can infer that all the fluorine atoms have 9 protons and 10 neutrons ( it's easy to observe in the periodic table that the masses are not exactly).

Then, we can infer for the information that fluorine has no common isotopes.

You might be interested in

Wskaż substancję, która ma największą zawartość procentową węgla w cząsteczce:

MrRa [10]

Answer: C2H4

Explanation:

The percentage composition of ethanol ( C2H5OH ) consist of 52.2% Carbon, Hydrogen of 13.0 and 34.8% of Oxygen.

The percentage composition of ethane gas (C2H6) consist of 80.0% carbon and 20.0% hydrogen.

The composition of Ethylene Glycols i.e C2H4(OH)2 is Carbon of 39.7%, 9.7% hydrogen and 51.6% oxygen.

The percent composition of c2h4 is 86% carbon, and 14% hydrogen.

From the information given, the substance with the highest percentage of carbon is C2H4

7 0

3 years ago

Write the fraction of the mass of kcl produced from 1 g of k2c03

Minchanka [31]

Mass of KCl= 1.08 g

<h3>Further explanation</h3>

Given

1 g of K₂CO₃

Required

Mass of KCl

Solution

Reaction

K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂

mol of K₂CO₃(MW=138 g/mol) :

= 1 g : 138 g/mol

= 0.00725

From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :

= 2/1 x mol K₂CO₃

= 2/1 x 0.00725

= 0.0145

Mass of KCl(MW=74.5 g/mol) :

= mol x MW

= 0.0145 x 74.5

= 1.08 g

6 0

3 years ago

Please help me vote you brainiest

bekas [8.4K]

Explanation:

An object in motion <u>stays</u> <u>at</u> motion An object <u>at</u> <u>rest</u> stays at rest unless acted by an <u>external</u> force.

[ Newton's 1st law of motion ]

6 0

2 years ago

The charges of a set of isoelectronic ions vary from 3+ to 3-. Place the ions in order of increasing size.

ser-zykov [4K]

Answer:

Explanation:

Iso-electronic species have same number of electrons . Positive charged ions will have smaller size . As electrons add , size increases due to electronic repulsion .

Following species are isoelectronic .

Al³⁺ < Mg²⁺ < Na¹⁺ < Ne < F⁻¹ < O⁻² < N⁻³

4 0

2 years ago

A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r

Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

$P\cdot V = n\cdot R\cdot T$ ,

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of gas particles in the gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume $V$ of the gas. Rearrange the ideal gas equation for volume:

$V = \dfrac{n \cdot R \cdot T}{P}$ .

Both the temperature of the gas, $T$ , and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

$T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K}$ ,
$T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}$ .

The volume of the gas is proportional to its temperature if both $n$ and $P$ stay constant.

$n$ won't change unless the balloon leaks, and
consider $P$ to be constant, for calculations that include $T$ .

$V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}$ .

Now, keep the temperature at $T_1 =258.65\;\text{K}$ and change the pressure on the gas:

$P_1 = 0.995\;\text{atm}$ ,
$P_2 = 0.720\;\text{atm}$ .

The volume of the gas is proportional to the reciprocal of its absolute temperature $\dfrac{1}{T}$ if both $n$ and $T$ stays constant. In other words,

$V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}$

(3 sig. fig. as in the question.).

See if you get the same result if you hold $T$ constant, change $P$ , and then move on to change $T$ .

6 0

2 years ago