Answer:
40.5 g of P₄O₁₀ are produced
Explanation:
We state the reaction:
P₄ + 5O₂ → P₄O₁₀
We do not have data from P₄ so we assume, it's the excess reactant.
We need to determine mass of oxygen and we only have volumne so we need to apply density.
Density = mass / volume, so Mass = density . volume
Denstiy of oxygen at STP is: 1.429 g/L
1.429 g/L . 16.2L = 23.15 g
We determine the moles: 23.15 g . 1mol / 33.472g = 0.692 moles
5 moles of O₂ can produce 1 mol of P₄O₁₀
Our 0.692 moles may produce (0.692 . 1)/ 5 = 0.138 moles
We determine the mass of product:
0.138 mol . 292.88 g/mol = 40.5 g
Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series
Explanation:
Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.
Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.
In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .
Thus for mass number : 235 = 207+4X
4X= 28
X = 7
Thus for atomic number : 92 = 82+2X-Y
2X- Y = 10
2(7) - Y= 10
14-10 = Y
Y= 4
Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series
It’s all based on you but yours could be anything hard you went through and how you overcame it. Also say how it made you the person you are today
The charge of an e- is 1.60217657×10^-19 coulombs I.e. A very small number!
So 1 coulomb is much much bigger than the charge of an electron.
Answer:
C₃H₃NaO₂
Explanation:
The percentage composition of the artificial snow is given.
The smallest whole number ratio of the atoms in a compound gives the empirical formula.
To find the empirical formula of the artificial snow, we use the method below;
Percentage composition of oxygen = 100 - (38.3+3.33+ 24.4) = 33.97
Elements C H Na O
Percentage
Composition 38.3 3.22 24.4 33.97
Number of
moles 38.3/12 3.22/1 24.4/23 33.97/16
3.19 3.22 1.06 2.12
Divide by
the smallest 3.19/1.06 3.22/1.06 1.06/1.06 2.12/1.06
3 3 1 2
The empirical formula of the compound is C₃H₃NaO₂
