Answer:
We need 12.26 grams H2SO4
Explanation:
Step 1: Data given
Volume of a H2SO4 solution = 500 mL = 0.500 L
Concentration of the H2SO4 solution = 0.250 M
Molar mass of H2SO4 = 98.08 g/mol
Step 2: Calculate moles H2SO4
Moles H2SO4 = concentration * volume
Moles H2SO4 = 0.250 M * 0.500 L
Moles H2SO4 = 0.125 moles
Step 3: Calculate mass of H2SO4
Mass of H2SO4 = moles * molar mass
Mass of H2SO4 = 0.125 moles * 98.08 g/mol
Mass of H2SO4 = 12.26 grams
We need 12.26 grams H2SO4
Breathing,Moving,Hunger,and the need to. Drink water
Answer:
1.175 M
Explanation:
Mass = 32.9 g
Volume = 700.0 mL = 0.7 L
Molarity = ?
The relationship between the quantities is given by;
Molarity = Number of moles / Volume
Number pf moles = Mass /Molar mass
Number of moles = 32.9 / 40 = 0.8225 mol
Molarity = 0.8225 / 0.7 = 1.175 M
Answer:
0.4g
Explanation:
1.0% (w/v%) = 1 g of agarose 100 ml of Tris-Acetate-EDTA, this is the buffer that agarose is run with
the amount of agarose for 40 ml = 1 /100 × 40 ml = 0.4 g