Answer:
about 2949 feet
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...
Tan = Opposite/Adjacent
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<h3>setup</h3>
Filling in the known values, we have ...
tan(6°) = (310 ft)/(distance to coyote)
<h3>solution</h3>
Multiplying by (distance to coyote)/tan(6°) gives ...
distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft
distance to coyote ≈ 2949.453 ft
The coyote is about 2949 feet from the base of the cliff.
Answer:
0.6708 or 67.08%
Step-by-step explanation:
Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

There is a 0.6708 probability that Helen makes both free throws.
No I do not know how to do this
The answer to your question is C.
I believe the answer would be B, good luck