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artcher [175]
3 years ago
10

Divide 2x^3+4x^2+5 by x-3 using long division.

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

2x^2 + 10x + 30 + 95/x-3

Step-by-step explanation:

Hope this helps!

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A rectangular pool is 12m long and 6m wide. A walkway of uniform width surrounds the pool. If the area of the walkway is 9m squa
Musya8 [376]
The walkway is 1.5 m wide.

The area of the pool is 12(6) = 72 m².

Adding a walkway of unknown width, x, around all 4 sides of the pool increases the width by 2x and the length by 2x; thus the area of the entire pool and walkway together would be given by

(12+2x)(6+2x)

We know that the area of just the walkway is 9 m² less than the area of the pool.  This means that:

(12+2x)(6+2x)-72 = 72-9

Multiplying through we have:
12*6+12*2x+2x*6+2x*2x - 72 = 63
72 + 24x + 12x + 4x² - 72 = 63
24x + 12x + 4x² = 63
36x + 4x² = 63

Writing in standard form we have:
4x² + 36x = 63

We want to set it equal to 0 to solve, so subtract 63 from both sides:
4x² + 36x - 63 = 63 - 63
4x² + 36x - 63 = 0

Using the quadratic formula, 

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-36\pm \sqrt{36^2-4(4)(-63)}}{2(4)}
\\
\\=\frac{-36\pm \sqrt{1296--1008}}{8}=\frac{-36\pm \sqrt{1296+1008}}{8}
\\
\\=\frac{-36\pm \sqrt{2304}}{8}=\frac{-36\pm 48}{8}=\frac{-36+48}{8}\text{ or }\frac{-36-48}{8}
\\
\\=\frac{12}{8} \text{ or }\frac{-84}{8}=1.5 \text{ or }-10.5

Since a negative width makes no sense, the walkway is 1.5 m wide.
8 0
3 years ago
Please help solve this one and also show work. Thank you!
avanturin [10]

1 lap has a distance of 1/3 miles.

So 5 laps have a distance of 5/3 miles.

Since Kim wants to run a total of 2 miles (6/3 miles), she will need to run 1 more lap.

5 0
3 years ago
10 points)<br> (07.01 HC)<br> Prove that the two circles shown below are similar.<br> Essay question
Lapatulllka [165]

Answer:

The circles are similar.

Step-by-step explanation:

You can move the small circle 3 units to the right and then 5 units up. The center of the small circle will also be the center of the larger circle. Then you dilate the small circle by a scale factor of 5 to get the larger circle.

3 0
3 years ago
DescriptionIn mathematics, the Poincaré conjecture is a theorem about the characterization of the 3-sphere, which is the hypersp
marishachu [46]
I believe you are right
6 0
3 years ago
In a study of the relationship of the shape of a tablet to its dissolution time, 6 disk-shaped ibuprofen tablets and 8 oval-shap
OLga [1]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. Let μ1 be the mean dissolution time for disk-shaped ibuprofen tablets and μ2 be the mean dissolution time for oval-shaped ibuprofen tablets.

The random variable is μ1 - μ2 = difference in the mean dissolution time for disk-shaped ibuprofen tablets and the mean dissolution time for oval-shaped ibuprofen tablets.

We would set up the hypothesis.

a) The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

This is a two tailed test.

For disk shaped,

Mean, x1 = (269.0 + 249.3 + 255.2 + 252.7 + 247.0 + 261.6)/6 = 255.8

Standard deviation = √(summation(x - mean)²/n

n1 = 6

Summation(x - mean)² = (269 - 255.8)^2 + (249.3 - 255.8)^2 + (255.2 - 255.8)^2+ (252.7 - 255.8)^2 + (247 - 255.8)^2 + (261.6 - 255.8)^2 = 337.54

Standard deviation, s1 = √(337.54/6) = 7.5

For oval shaped,

Mean, x2 = (268.8 + 260 + 273.5 + 253.9 + 278.5 + 289.4 + 261.6 + 280.2)/8 = 270.7375

n2 = 8

Summation(x - mean)² = (268.8 - 270.7375)^2 + (260 - 270.7375)^2 + (273.5 - 270.7375)^2+ (253.9 - 270.7375)^2 + (278.5 - 270.7375)^2 + (289.4 - 270.7375)^2 + (261.6 - 270.7375)^2 + (280.2 - 270.7375)^2 = 991.75875

Standard deviation, s2 = √(991.75875/8) = 11.1

b) Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

Therefore,

t = (255.8 - 270.7375)/√(7.5²/6 + 11.1²/8)

t = - 3

c) The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [7.5²/6 + 11.1²/8]²/[(1/6 - 1)(7.5²/6)² + (1/8 - 1)(11.1²/8)²] = 613.86/51.46

df = 12

We would determine the probability value from the t test calculator. It becomes

p value = 0.011

d) Since alpha, 0.05 > than the p value, 0.011, then we would reject the null hypothesis. Therefore, we can conclude that at 5% significance level, the mean dissolve times differ between the two shapes

4 0
3 years ago
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