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3 years ago

13

Please be quick, I need this really soon!

1 answer:

Elena-2011 [213]3 years ago

8 0

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish the simple interest formula which we will require to solve this problem as displayed below:

Simple Interest = Principal × Rate of Interest × No. of Time Periods

I = PRN

Now let's substitute the values from the problem into this formula and solve as displayed below:

I = $15

P = $150

R = ?

N = 2 years

I = PRN

15 = 150 × R / 100 × 2

R / 100 = 15 / ( 150 × 2 )

R / 100 = 15 / 300

R = 5 / 100 × 100

R = 5%

ANSWER:

The simple annual interest rate for the loan is 5%. Therefore, the answer is:

B ) 5.0%

Please mark as brainliest if you found this helpful! :)
Thank you <3

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By geometry,
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Answer:

y + 2 = 2/3(x + 2)

Step-by-step explanation:

Slope = 2/3 (rise/run)

Point: (-2,-2)

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3 years ago

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Angelina_Jolie [31]

The answer is
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3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

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a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

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lubasha [3.4K]

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Step-by-step explanation:

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