C
Mathy49 See you later lol deleted my old one cuz it's in spanish
Answer:
Manish has Rs630 while Jhanavi has Rs168.
Step-by-step explanation:
The fraction Manish would have left would be subtracting the fraction on savings as well as that spent on the mall. Which would be;
1 -( 1/2 + 1/4)=1 -3/4 = 1/4
Meaning Manish had 1/4 of his allowance left on him.
Which means 1/4 × Rs. 2520=Rs630
Similarly for Jhanavi, we have :
The fraction left as
1-(1/3 +3/5) = 1 - ( 14/15) = 1/15
Meaning 1/15 of the allowance got remains which is;
1/15 × Rs. 2520= Rs.168
X + x -30 = 2022x - 30 = 2022x = 232x =116 first game = 116second game = 116 - 30 = 86116 + 86 = 202 second game = 86
<span>X+(X+2)=32
2X+2=32
2X=32-2
2X=30
X=30/2
X=15 ANSWER FOR THE FIRST ODD NUMBER.
15+2=17 FOR THE OTHER ODD NUMBER.
15*17=255 ANSWER FOR THE PRODUCT OF THESE 2 ODD NUMBERS.</span>
Answer:
B.
Step-by-step explanation:
For reference, the median for housecats is 11 and the median for small dogs is 9. So, by process of elimination, B is the correct answer.
