Question

A coordinate plane with a line passing through (0, negative 4) and (2, 0). What is the equation of the graphed line written in standard form? 2x – y = –4 2x – y = 4 y = 2x – 4 y equals StartFraction one-half EndFraction x minus 4.

Answer 1

Answer:

d) The equation of the line passing through the points

$y = \frac{-x}{2} - 4$

Step-by-step explanation:

Step(i):-

Given points are ( 0, -4) and (2 ,0)

slope of the line

               $m = \frac{y_{2}- y_{1} }{x_{2}- x_{1} } = \frac{2-0}{0-4} = \frac{-2}{4}= \frac{-1}{2}$

Step(ii):-

The equation of the line passing through the point ( 0,-4) and having slope

$m = \frac{-1}{2}$

$y - y_{1} = m ( x - x_{1} )$

$y - (-4) = \frac{-1}{2} ( x - 0 )$

2 ( y +4) = -x

2 y + 8 = -x

2 y = - x - 8

 $y = \frac{-x}{2} - \frac{8}{2}$

 $y = \frac{-x}{2} - 4$

Final answer:-

The equation of the line passing through the points

$y = \frac{-x}{2} - 4$

Answer 2

Answer: B

Step-by-step explanation:

2x – y = 4. remember to make x zero then y to find the points on the coordinate plane. (I did get this answer right on the test).