Put in terms of a
b=2a
a=a
c=a-15000
2a+a+a-15000=109000
2a+a+a=124000
4a=124000
a=31000
Candidate B received 62000 votes
Greater than 1 because left side is a fraction less than 1 and right side is a number greater than 1.
The left side being a fraction less than 1 could only mean that you have to multiply a number greater than 1 to the other side. And since the other side is a number greater already than 1 then multiplying the left side to the right side must result in a number greater than 1.
Answer:
20 days
Step-by-step explanation:
Answer: 9 (with a margin of: 0)
Step-by-step explanation:
Times everything by 5
That gives you 15 + 10w = 105.
Subtract 15 from both sides
Divide by 10 to get w by itself
Then you solve
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
