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3 years ago

7

Describe the connections between unit rates, proportions, and rate tables.

2 answers:

Bas_tet [7]3 years ago

5 0

They're all used for differentiating types of measurement in mathematics and science.

In-s [12.5K]3 years ago

3 0

I agree with ICHIGOBUNNI

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2ln(5x)=8 solve for x

White raven [17]

$lnx=log_ex\\----------\\log_ab=c\iff a^c=b\\----------\\Domain:\\5x > 0\ \ \ |divide\ both\ sides\ by\ 5\\x > 0\\D:x\in\mathbb{R^+}\\----------------------\\2ln(5x)=8\ \ \ \ |divide\ both\ sides\ by\ 2\\\\ln(5x)=4\iff e^4=5x\\\\5x=e^4\ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{x=\frac{e^4}{5}\in D}$

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3 years ago

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A figure has side lengths as marked in the diagram. <br> What is the area of the figure?

vovangra [49]

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132.4

Step-by-step explanation:

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3 years ago

What is -138 divided by 18

balu736 [363]

-138/18= -7.6 repeating

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3 years ago

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In-s [12.5K]

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2 years ago

5+ 3 cos ½x = 7<br>how to find the x?

Anon25 [30]

Answer:

$x=\pm 2 arcos(\frac{2}{3})+4k\pi$

where $k$ is an integer

Step-by-step explanation:

$5+3\cos(\frac{1}{2}x)=7$

We are going to isolate the trig expression first.

Subtract 5 on both sides:

$3\cos(\frac{1}{2}x)=2$

Divide both sides by 3:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

Now since $\cos(u)$ is even then $\cos(u)=\cos(-u)$ .

So we have:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

implies:

$\frac{1}{2}x=arccos(\frac{2}{3})+2k\pi$

Multiply both sides by 2:

$x=2arccos(\frac{2}{3})+4k\pi$

or

$-\frac{1}{2}x=arcos(\frac{2}{3})+2k\pi$

Multiply both sides by -2:

$x=-2arccos(\frac{2}{3})-4k\pi$

So we can say the solution is:

$x=\pm 2arcos(\frac{2}{3})+4k\pi$

( $k$ is an integer)

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2 years ago