All categories

3 years ago

-4(w+1)=-24 what does w equal?

Mathematics

2 answers:

makvit [3.9K]3 years ago

8 0

Answer:

w=5

Step-by-step explanation:

using the distributive property to simplify the equation

-4(w)+1(-4)=-24 so

-4w-4=-24 (adding 4 to both sides)

-4w==20 (divide by -4)

w=5

Agata [3.3K]3 years ago

5 0

Answer:

w=5

Step-by-step explanation:

-4(w+1)=-24

times -4 with everything in the brackets

=-4w-4=-24

+4 on both sides

-4w=-20

divide by 4

w=5

You might be interested in

A store donated cases of crayons to a daycare center. Each case holds 24 boxes of crayons; each box holds 8 crayons. How many cr

kakasveta [241]

Answer:

192

Step-by-step explanation:

Just multiply 24 by 8.

I think thats it tho.

4 0

3 years ago

Read 2 more answers

What is the inverse of g(x) =<br> X +8

gayaneshka [121]

Answer:

The inverse is x-8

Step-by-step explanation:

g(x) = x+8

y = x+8

To find the inverse, exchange x and y

x = y+8

Solve for y

Subtract 8 from each side

x-8 = y+8-8

x-8 = y

The inverse is x-8

6 0

3 years ago

Help if you want brianleist!! :) uhm don't mind update- NO LINkS- Thank you to those who help! :)

marta [7]

The answer would be 2 I’m pretty sure

3 0

3 years ago

Read 2 more answers

aj paid $31.86 for a new basketball. The price he paid included sales tax of 6.25%. Which equation can be used to find the price

asambeis [7]

It A)<span>p + 0.0625p = 31.86</span>

5 0

3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

4 years ago