Let
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + 6 = fourth odd integer
x + (x + 2) + (x + 4) + (x + 6) = -200
4x = -200 - 2 - 4 - 6
4x = -212
x = -53
Therefore, the four consecutive integers are -53, -51, -49, -47.
2100$ you earn a month because you multiply 15 and 35 and u get 525 then multiply that by 4 since that’s how many weeks are in a month and u get 2100
Answer:
1) N = 2. 2) -7/3
Step-by-step explanation:
1)
6 = 3n
6/3 = n
2 = n
n = 2
2)
-3 = 3t + 4
3t + 4 = -3
3t = -3 - 4
3t = -7
T = -7/3
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
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