Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Answer:

Step-by-step explanation:
Given

Required
Determine the amount of sweet Ivy gets when Dennis = 42
We have:
and

Substitute 42 for Dennis in 

Convert to fraction

Cross Multiply:

Divide through by 7




Step-by-step explanation:
The expressions are not properly written
Given
RS = 4x – 9
ST = 19
RT = 8x – 14
Based on the given parameters, the addition postulate below is true
RS+ST = RT
Substitute
4x-9+19 = 8x-14
collect like terms
4x-8x = -14-19+9
-4x = -33+9
-4x = -24
x = -24/-4
x = 6
Get RS:
RS = 4x-9
RS = 4(6)- 9
RS = 24-9
RS = 15
Get RT:
RT = 8x - 14
RT = 8(6)-14
RT = 48-14
RT = 34
From the identity:


the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)

Answer: b. g(x)=cos^-1(1/x)