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Natalka [10]
3 years ago
9

Dan earns £276 over the course of a five-day week. How much is that per day?

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0

Answer:

£55.2

Step-by-step explanation:

Five day earning is £276

Earning per day is £276/5=£55.2

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Use the slope formula to find the slope of the line passing through the given points.
irina1246 [14]
The slope is undefined because it is a vertical line on the x axis at 0. Its a straight line going up
3 0
3 years ago
How many pieces of ribbon can you cut from 10 meters, if each piece is 4<br>cm long?​
malfutka [58]

Answer:

answer:250 pieces

1 metre=100cm so

10metres =100*10 =1000cm

each piece is 4 CM long, so.,

no. of pieces=1000/4

by dividing by 2....

=500/4

again by dividing by2...

=250/1=250 pieces

so 250 pieces of ribbon can be cuttted from 10 metre long ribbon.

7 0
3 years ago
Need Help with some Math
tatyana61 [14]

Answer:

8

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. The PRT states that if we have a polynomial f(x) being divided by a factor in the form of (x-a), then the remainder of the polynomial is given by f(a).

We have the polynomial:

f(x)=3x^{15}-5x^{12}+7x^6-3x^2+12

And it is being divided by:

(x+1)

We can rewrite our factor as:

(x-(-1))

Therefore:

a=-1

Then our remainder will be:

f(-1)

Evaluate:

\begin{aligned} f(-1)&=3(-1)^{15}-5(-1)^{12}+7(-1)^6-3(-1)^2+12\\&=-3-5+7-3+12\\&=8 \end{aligned}

So, our remainder will be 8.  

4 0
3 years ago
What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y
pochemuha

For this case we must simplify the following expression:

\sqrt [3] {\frac {12x ^ 2} {16y}}

We rewrite the expression as:

\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=

We multiply the numerator and denominator by:

(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=

We use the rule of powera ^ n * a ^ m = a ^ {n + m} in the denominator:

\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=

Move the exponent within the radical:

\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=

\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=

\frac{\sqrt[3]{6x^2*y^2}}{2y}

Answer:

\frac{\sqrt[3]{6x^2*y^2}}{2y}

7 0
3 years ago
Read 2 more answers
What is the equation of the following graph in vertex form? PLEASE HELP ME!
viktelen [127]

Answer: Choice B

y = (x+3)^2 - 1

==================================================

Recall that vertex form is y = a(x-h)^2 + k with the vertex being (h,k)

From the given graph, it shows that (h,k) = (-3,1) is the vertex. So we plug this pair of values into the general function above to get

y = a(x-h)^2 + k

y = 1(x-(-3))^2 + (-1)

y = (x+3)^2 - 1

which is the final answer

note: a = 1 is the case for all four answer choices, so we don't have to worry about the value of 'a'

6 0
3 years ago
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