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m_a_m_a [10]
4 years ago
14

Conrad and jill have a taxable income of 63,670. they discovered that they are able to receive $1,500 tax credit for purchasing

an energy efficient furnace. How will this tax credit affect their taxes?
A) the tax credit will increase their taxable income by $1,500
B) the tax credit will reduce their taxable income by $1,500
C) the tax credit is added to the tax owed, not the taxable income
D) the tax credit is subtracted from the tax owed, not taxable income
Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
7 0
 The answer is letter D. The tax credit will be subtracted from the tax owed, not taxable income. This is because a tax credit is something that will be deducted or offset to your liability and that is the tax you owed based on your own taxable income. 
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A carpenter charges $720 for 18 hours of work. She charges the same amount of money for each hour of work.
Rainbow [258]

Answer:

A

Step-by-step explanation:

To start off, you know 18 hours= 720

So you could automatically get rid of B and D since 19 and 17 are not 18.

After that, you have it down to A and C. The way you would find how much she charges for one hour is dividing 720 by 18. When you do that it means you are divding 720$ into 18 different groups each group representing an hour. When you divide 720 by 18 you should get 40. So every hour she makes 40 dollars. 40x 2 hours is 80. I hope I helped you!

3 0
3 years ago
Read 2 more answers
HELP PLZZ will give brainliest <3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
If we wanted to know how high a 5th-grade student could jump, how many students would be reasonable to test? 5, 12, 30, or 200.
77julia77 [94]
The right amount to test would be 30.

200 is to many kids and 12 is not enough.

Hope this Helps!!
4 0
3 years ago
HELPPPP WHATS THE LATERAL AREA
AVprozaik [17]

Answer:

3cm

Step-by-step explanation:

6 0
3 years ago
A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.
Softa [21]
We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
5 0
3 years ago
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