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Ad libitum [116K]
3 years ago
7

Three times the square of a nonzero number is equal to twelve times the number.

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
Well if you write the statement as an equation then that will get you

3*x^2 = 12x

Now we just solve.  You can divide both sides by 3x and that gives you x = 4
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Evan paid $60.54 for 3 notebooks and a calculator. If the calculator costs $45.87, how much does each notebook cost? Write a two
Aleonysh [2.5K]

Answer:   4.89$

Step-by-step explanation:

60.54 is starting amount then subtract 45.87 left with 14.67 then divide by 3 get 4.89

60.54-45.87=14.67

14.67/3=4.89

7 0
3 years ago
Read 2 more answers
Multiple and convert to simplest form​
Lady bird [3.3K]

Answer:

1)4

2)28

3)18.3

4)38.5

5)22.5

6)19.25

7)25.5

8)69.666

9)6.5

10)22.666

Step-by-step explanation:

  • To do this first you should convert the mix numbers into inproper fractions and then solve.

1)8/5*5/2=4

2)21/5*20/3=7*4

                  =28

3)33/4*20/9=11*5/3

                   =55/3

                   =18.33...

                   =18.3

4)35/6*33/5=7*11/2

                   =77/2

                   =38.5

5)22/8*90/11=45/2

                    =22.5

6)11/3*21/4=11*7/4

                 =77/4

                 =19.25

7)34/5*15/4=34*3/4

                  =25.5

8)22/3*57/6=11*19/3

                   =209/3

                   =69.666

9)39/8*4/3=13/2

                 =6.5

10)17/2*8/3=17*4/3

                 =68/3

                 =22.666

<em>Hope you got this</em>

<em>If you have any doubt please ask me</em>

<em>If you need this in fraction form just check the attachment</em>

5 0
3 years ago
Hey Friends!! Wanna talk and chill?
Ivan

Answer:

say less

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A certain isotope decays so that the amount A remaining after t years is given by: A = A0 · e ^-0.03t where A0 is the original a
Katena32 [7]
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k  (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187 </span>
about 23 years
</span></span>
7 0
3 years ago
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PLEASE ANSWER! WILL MARK BRAINLIEST!!
lord [1]

Answer:

Here you go.Hope this help!!

5 0
2 years ago
Read 2 more answers
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