3 years ago

PLEASE HELP ME!!! THIS IS URGENT!!! DUE IN 5 MINUTES!!! LOOK AT THE IMAGE

Mathematics

1 answer:

disa [49]3 years ago

3 0

Answer:

1,5

Step-by-step explanation:

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I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B8a%5E%7B-5%7Db%5E%7B4%7D%20%7D%7B12a%5E%7B-6%7Db%5E%7B-2%7D%20%7D%29" id="TexForm

Dima020 [189]

2ab6/3 is the awnser for this one

4 0

2 years ago

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Someone please help :(

OleMash [197]

The answer would be answer choice a.

Because 5/4 = 1.25
tan (51) = 1.235
tan (45) = 1
tan (60) = 1.732
tan (57) = 1.5399

The closest to 1.25 is tan (51)

Hope this helps :)

3 0

3 years ago

Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17).

Brilliant_brown [7]

Answer:

x^4 +y+1

Step-by-step explanation:

6 0

3 years ago

I need help ASAP ?!?!?!?!?!

kotegsom [21]

I am doing the same thing

4 0

3 years ago

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