Answer: Regular nonagon
Step-by-step explanation: In image
Answer:
.5 miles per 1hr
Step-by-step explanation:
the unit rate is distance per 1 hr. your goal is to change 3/4 hr to 1 hr. how do you do this? you multiply the inverse of 3/4 (4/3) by both sides. ex
3/8mile per 3/4hr
×4/3
.5 mile per 1 hr
Answer:
![v_f=9.0774m/s](https://tex.z-dn.net/?f=v_f%3D9.0774m%2Fs)
Step-by-step explanation:
Let's assume
initial velocity =vi
final velocity=vf
initial height =hi
final height =hf
acceleration due to gravity =g
we can use formula
![\frac{1}{2}v_i^2+gh_i= \frac{1}{2}v_f^2+gh_f](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dv_i%5E2%2Bgh_i%3D%20%5Cfrac%7B1%7D%7B2%7Dv_f%5E2%2Bgh_f)
we are given
![v_i=2m/s](https://tex.z-dn.net/?f=v_i%3D2m%2Fs)
![h_i=2\times 2=4](https://tex.z-dn.net/?f=h_i%3D2%5Ctimes%202%3D4)
![h_f=0](https://tex.z-dn.net/?f=h_f%3D0)
![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
now, we can plug values
![\frac{1}{2}(2)^2+(9.8)(4)= \frac{1}{2}v_f^2+(9.8)(0)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%282%29%5E2%2B%289.8%29%284%29%3D%20%5Cfrac%7B1%7D%7B2%7Dv_f%5E2%2B%289.8%29%280%29)
now, we can solve for vf
![\frac{1}{2}(2)^2+(9.8)(4)= \frac{1}{2}v_f^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%282%29%5E2%2B%289.8%29%284%29%3D%20%5Cfrac%7B1%7D%7B2%7Dv_f%5E2)
we get
![v_f=9.0774m/s](https://tex.z-dn.net/?f=v_f%3D9.0774m%2Fs)
Answer:
Option 1) ![x=-2+i\sqrt{2}](https://tex.z-dn.net/?f=x%3D-2%2Bi%5Csqrt%7B2%7D)
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
![x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
so
substitute in the formula
![x=\frac{-4\pm\sqrt{4^{2}-4(1)(6)}} {2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-4%5Cpm%5Csqrt%7B4%5E%7B2%7D-4%281%29%286%29%7D%7D%20%7B2%281%29%7D)
![x=\frac{-4\pm\sqrt{-8}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-4%5Cpm%5Csqrt%7B-8%7D%7D%20%7B2%7D)
Remember that
![i=\sqrt{-1}](https://tex.z-dn.net/?f=i%3D%5Csqrt%7B-1%7D)
so
![x=\frac{-4\pm i\sqrt{8}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-4%5Cpm%20i%5Csqrt%7B8%7D%7D%20%7B2%7D)
![x=\frac{-4\pm2i\sqrt{2}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-4%5Cpm2i%5Csqrt%7B2%7D%7D%20%7B2%7D)
![x=-2\pm i\sqrt{2}](https://tex.z-dn.net/?f=x%3D-2%5Cpm%20i%5Csqrt%7B2%7D)
The solutions are
![x=-2+i\sqrt{2}](https://tex.z-dn.net/?f=x%3D-2%2Bi%5Csqrt%7B2%7D)
and
![x=-2-i\sqrt{2}](https://tex.z-dn.net/?f=x%3D-2-i%5Csqrt%7B2%7D)
Answer:
x = 18
Step-by-step explanation:
diagonals bisect each other so 12x = 216
x = 216/12
x = 18