Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
19 i think though im pretty sure it is
Answer:
Team Nara collected more water
1.402 > 1.045
so team nara wins
Answer:
No Solution.
Step-by-step explanation:
Equality equation:
— 2y – Зу +8 = 8 — 5у – 12 (Given)
-5y + 8 = -4 - 5y (distributive property of equality)
-5y = -12 - 5y (subtraction property of equality)
= -12 (addition property of equality)
when you add 5y on both sides it cancels the 5y out, it's no solution.
<em><u>Ace-The Kid Laroi</u></em>