Question

Hey can you please help me posted picture of question

Answer 1

Answer:
(x+4)(x+5) = 0

Explanation:
The standard form of the quadratic equation is:
ax² + bx + c = 0

The given equation is:
x² + 20 = -9x
Adding 9x to both sides would make us reach the standard form which would be:
x² + 9x + 20 = 0
By comparison:
a = 1
b = 9
c = 20

To factor the equation, we would need to use the quadratic formula shown in the attached image.

By substitution, we ould find that:
either x = $\frac{-9+ \sqrt{(9)^2-4(1)(20)} }{2(1)} = -4$

This means that the first factor is (x+4)

or x = $\frac{-9+ \sqrt{(9)^2-4(1)(20)} }{2(1)} = -5$

This means that the second factor is (x+5)

Based on the above, the factored form of the equation would be:
(x+4)(x+5) = 0

Hope this helps :)

Answer 2

The original question is going to be a quadratic, so it has to equal 0. To do this, we add the 9x to both sides and put it in order. Afterward, we split the equation apart. Work is shown below.

$x^{2}$ + 20 = -9x
$x^{2}$ + 9x + 20 = 0
(x +  )(x+   ).                                        We know they are both positive because 9x        ...                                                        and 20 are both positive.
(x + 4)(x + 5) = 0

I hope this helps!