Gggggghhhhhbhhjnjjnjjjjjjjjjjjjjkk
Answer:12
Step-by-step explanation:hxdhvxrjjnvcxx
Answer: 15
Step-by-step explanation:
9514 1404 393
Answer:
Step-by-step explanation:
We can start with the point-slope form of the equation for a line. To meet the given requirements, we can use a point of (5, 0) and a slope of -1. Then the equation in that form is ...
y -0 = -1(x -5)
Simplifying gives the slope-intercept form:
y = -x +5 . . . . . . . use the distributive property to eliminate parentheses
Adding x to both sides gives the standard form:
x + y = 5
__
<em>Explanation</em>
We know the line has the required intercept and slope because we chose those values to put into the point-slope form. Conversion from one form to another made use of the rules of equality, the additive identity element (y-0=y), and the distributive property.
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
