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Margarita [4]
3 years ago
11

In a computer game, a bird flies at a height of 1,281 feet. At the same time, a fish swims 282 feet below sea level. What is the

difference between the height of the bird and the depth of the fish?
Mathematics
2 answers:
pantera1 [17]3 years ago
7 0

Answer:

For TTM it's 1,563

fenix001 [56]3 years ago
6 0
To find the difference, we need to subtract the height of the fish from the height of the bird. If we use sea level as 0, then the bird flies at 1,281 feet, and the fish swims at -282 feet.

1,281 - (-282) = <span>1,281 + 282 = 1,563 feet

There is a </span><span>1,563 feet difference between the height of the bird and the depth of the fish</span>
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kifflom [539]

Answer:

1. 360

2. Yes because in a regular hexagon all angles are congruent so the exterior angles are as well

3. (i) 60 (ii) 120

4.

(i) 1. 360 2. Yes because in a regular octagon all angles are congruent so the exterior angles are as well 3. (i) 45 (ii) 135

(ii) 1. 360 2. Yes because in a regular 20-gon all angles are congruent so the exterior angles are as well 3. (i) 18 (ii) 162

Step-by-step explanation:

Works for each polygon

1. First take the number of sides and subtract it by 2 then multibly that by 180

6-2=4x180=720

Then divide by the number of angles and subrtact that number by 180 to find the measure of one exterior angle

720/6=120

180-120=60

Then multiply by the number of exterior angles

60x6=360

2. Regular polygons always have equal angles so the exterior angles are as well

3. Put in your numbers from earlier

(i) 60 (ii)120

Hope this helps! :)

P.S. Feel free to mark brainliest :)

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