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Brums [2.3K]
3 years ago
5

Fay has a lemonade stand. She spends £35 on ingredients. She sells each glass of lemonade for £2.10. If she sells 50 glasses of

lemonade, what is her total profit?
Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

£70.00

Step-by-step explanation:

You basically want to find what she spent in total, then subtract the amount she spent on ingredients.

50 glasses of lemonade at £2.10 each would be £105. (50*2.1)

Subtract the cost of ingredients, which is £35, with the total she made, £105, to get £70 (105-35)

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Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14
adoni [48]
Let 2x – y = 3 ——— equation 1

Let x + 5y = 14 ——— equation 2

Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

• Put eqn 3 in eqn 2

(y + 3 / 2) + 5y = 14

6y = 14 – 3/2

6y = 25/2

y = 25/12

• put y = 25/12 in eqn 3

x = (25/12 + 3/2)

x = 43/12
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3 years ago
What’s the slope-intercept for this equation???
andrezito [222]
Y= 2/3x + 10 (or 11?) is the equation
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2 years ago
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A couch and coffee table cost a total of $1080. The cost of the couch is two times the cost of the coffee table. Find the cost o
Alborosie

Answer:

$720

$360

Step-by-step explanation:

Let the cost of couch be A and that of coffee table be B

Given couch and coffee table cost $1080

That’s

A + B = $1080

Also, the cost of couch A is 2 times the cost of coffeee table B.

That’s

A = 2B

We now have two equations

A + B = 1080

A = 2B

Now ,substitute 2B for A in the first equation .

We have

A + B = 1080

2B + B = 1080

3B = 1080

Divide both sides by 3

3B/3 = 1080/3

B = 360

The coffee table cost $360

Remember A = 2B

Therefore

A = 2 x $360

A = $720

The couch cost $720 while the coffee table cost $360

3 0
3 years ago
Addie bought lunch to go from a sandwich shop. She spent $12.00 for a $10.00 meal. What percent was the tip?
horsena [70]

Answer:

She gave a $2.00 tip witch would be %20 of her meal cost.

Step-by-step explanation:

    </3 PureBeauty

4 0
2 years ago
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Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingb
ruslelena [56]

Answer: provided in the explanation segment

Step-by-step explanation:

(a). from the question, we can see that since that б is known, we can use standard normal, z.

we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?

⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;

x ± z * б / √m

which is

3.15 ± 1.28 * 0.32/√10

= 3.15 ± 0.1295 = 3.0205 or 3.2795

(b). normal distribution of weight (c) б is known

(c). option (a) and (e) are correct

(d).  from the question, let sample size be given as S

this gives';

1.28 * 0.32/√S = 0.15

√S = (1.28 * 0.32) / 0.15 = 2.73

S = 7.4529

cheers i hope this helps

6 0
2 years ago
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