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Nookie1986 [14]
3 years ago
12

Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

                 = - 5x + 3 + 3x - 7

                 = - 2x - 4

Then

a₁₃ = - 3x + 7 + 12(- 2x - 4)

     = - 3x + 7 - 24x - 48

     = - 27x - 41

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In triangle ABC, D is the midpoint of side AC and E is the midpoint of side BC.
cestrela7 [59]

Answer:

14

Step-by-step explanation:

Since all sides are half of greater triangle.Then 7 × 2 = 14 is length of greater hypotenuse.

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3 years ago
Sandy works at a clothing store. She makes $7 per hour plus earns 10% commission on her sales. She worked 72 hours over the last
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Find x round to the nearest tenth! please help!!! more trigonometry!​
hoa [83]

Answer:

<h2>x = 437.3 ft</h2>

Step-by-step explanation:

Look at the picture.

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6 0
3 years ago
QUESTION IS DOW BELOW 30 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
ivann1987 [24]

The required solution is ∠RQT =  202°  and ∠QTS = 51°

<h3 />

<h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.

Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.

Now, the given circle has a cyclic quadrilateral QRST in which it is given that  ∠RQT =  202° and ∠QRS = 129°

Since,sum of the opposite angles of a cyclic quadrilateral =  180°  

⇒∠QTS + ∠QRS = 180°

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⇒ ∠QTS = 180° - ∠129°

⇒ ∠QTS = 51°

Hence,the requires angles are ∠RQT =  202° and ∠QTS = 51°.

More about cyclic quadrilateral :

brainly.com/question/14323008

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2 years ago
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