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azamat
3 years ago
11

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the

machine recommends that the temperature of the part remain below 141°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by T=0.005x^2+0.45x+125. Will the temperature of the part ever reach or exceed 141°F? Use the discriminant of a quadratic equation to decide.​
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
6 0

Answer:

The temperature of the part won’t reach or exceed 141℉

Step-by-step explanation:

Substituting the value of T= 141 the given equation becomes

\begin{array}{l}{141=-0.005 x^{2}+0.45 x+125} \\ {-0.005 x^{2}+0.45 x+125-141=0} \\ {-0.005 x^{2}+0.45 x-16=0}\end{array}

we know that discriminant D = b^{2}-4 a c

Three conditions: - D < 0: imaginary roots, D = 0: real and equal roots,

D > 0: two real and unequal roots Substituting  a = -0.005, b = 0.045 and c = -16, \mathrm{D}=0.045^{2}-4(-0.005)(-16) \mathrm{D}=-0.317975 \mathrm{D}=-0.32(\text { approx. }) Therefore, it won't reach the temperature.

Zina [86]3 years ago
3 0

Answer:

No

Step-by-step explanation:

Just wanted to make it a little bit more clear on the matter of the answer

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Answer:

The answer will be:

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Step-by-step explanation:

The bracelets cost $2 and the earrings cost $3.

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inysia [295]

Answer:

1. k = 15

2. d = 20

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3 years ago
3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is
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4 0
3 years ago
Suppose that profit for a particular product is calculated using the linear equation: Profit = 20S + 3D. Which of the following
uranmaximum [27]

Answer:

b. S = 405, D = 0

Step-by-step explanation:

We have been given that profit for a particular product is calculated using the linear equation: \text{Profit}=20S+3D. We are asked to choose the combinations of S and D that would yield a maximum profit.

To solve our given problem, we will substitute given values of S and D in the profit function one by one.

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\text{Profit}=20(0)+3(0)

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\text{Profit}=20S+3D

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\text{Profit}=8100

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Since the combination S = 405, D = 0 gives the maximum profit ($8100), therefore, option 'b' is the correct choice.

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