Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Choice 2222222222222222222222222222222
Answer:
So 60% of this unknown number is 28
Let this unknown number be n
60/100 × n = 28
0.60 × n = 28
n = 28/0.6
n = 46.7
To the nearest wholw number is 47
So there are 47 votes in total
